Solve LeetCode 2: Add Two Numbers in Python with a digitwise carry approach. The key is to make the state invariant explicit, so the implementation and complexity follow naturally.
This guide paraphrases the task and does not reproduce LeetCode’s prompt. Use the official page for the complete statement, examples, constraints, and submission runner.
| Difficulty | Medium |
|---|---|
| Topic | Linked List |
| Reusable pattern | digitwise carry |
| Complexity | O(max(m,n)) time and O(max(m,n)) output space |
What the problem is testing
Walk both reverse-order digit lists, add available digits plus carry, and append the ones digit while carrying the tens digit.
Algorithm
- Walk both reverse-order digit lists, add available digits plus carry, and append the ones digit while carrying the tens digit.
- Maintain this invariant: The output prefix represents the exact sum of the processed digit positions.
- Continue until every input item or reachable state has been resolved, then return the accumulated result.
Python solution
LeetCode provides the list, tree, or graph node definition used by the method.
from collections import Counter, defaultdict, deque, OrderedDict
import random
class Solution:
def addTwoNumbers(self, l1, l2):
dummy = tail = ListNode()
carry = 0
while l1 or l2 or carry:
total = carry
if l1: total += l1.val; l1 = l1.next
if l2: total += l2.val; l2 = l2.next
carry, digit = divmod(total, 10)
tail.next = ListNode(digit)
tail = tail.next
return dummy.nextWhy this is correct
The proof follows the maintained state: The output prefix represents the exact sum of the processed digit positions. Each iteration preserves that claim while permanently resolving at least one position, node, interval, or search state. When the loop or recursion ends, every candidate required by the problem has therefore been included or ruled out, so the returned value is correct.
Complexity
O(max(m,n)) time and O(max(m,n)) output space. The stated auxiliary space excludes the returned output unless the output is the data structure being built.
Edge cases
A final carry creates a new node; lists can have different lengths.
Tested reference code
This implementation is included in the site’s downloadable 100-solution Python library. The complete suite compiles every solution and runs a behavioral assertion for every problem before publication.
Browse the searchable 100 LeetCode Python Solutions hub. Previous: 141. Linked List Cycle · Next: 21. Merge Two Sorted Lists